7. ∴ ∠AOB = ∠BOC = ∠COD = ∠DOA = 90º and AO = CO, BO = OD. Properties of Rectangle. There are several formulas for the rhombus that have to do with its: Sides (click for more detail). Tip: To visualize this one, take two pens or pencils of different lengths and make them cross each other at right angles and at their midpoints. Some of the important properties of the rhombus are as follows: All sides of the rhombus are equal. Since ∆AOB is a right triangle right-angle at O. M(-2,-1) A(0,5) T(6,3) H(4,-3) Answer Save. The diagonals of a rhombus bisect each other at right angles. Click hereto get an answer to your question ️ If the diagonals of a quadrilateral bisect each other, then prove that it is a parallelogram. For which quadrilateral are the diagonals are congruent but do not bisect each other? Contact. ie. The diagonals bisect each other perpendicularly. … OP = OB . State the definition of a parallelogram (the one in B&B). The area of rhombus is the plan enclosed by the sides of the rhombus. If you have any questions while trying to complete this investigation, or suggestions that would be useful, especially for use at the high school level, please send e-mail to esiwdivad@yahoo.com . So by angle-side-angle congruency, the two triangles are congruent to each other. Example 2 Show that the diagonals of a rhombus are perpendicular to each other. Diagonals bisect vertex angles. OP = OB . D. Answer link. Similarly we can prove that PC = PA . A rhombus is a type of parallelogram, and what distinguishes its shape is that all four of its sides are congruent.. Another way to prevent getting this page in the future is to use Privacy Pass. In a rhombus the diagonals are perpendicular and bisect each other.. T he diagonal of Rhombus intersect at O. AC is perpendicular to BD. For Study plan details. Thus, the diagonals of a rhombus bisect each other. How does Charle's law relate to breathing? - the diagonals bisect each other; - the opposite angles are congruent; - the sum of any two consecutive angles is equal to 180°. What are the units used for the ideal gas law? Not necessarily - the diagonals of a rhombus bisect each other (they are perpendicular bisectors of each other), but are not equal. - the diagonals bisect each other; - the opposite angles are congruent; - the sum of any two consecutive angles is equal to 180°. diagonal of a rhombus are perpendicular to each other. The opposite angles are congruent, the diagonals bisect each other, the opposite sides are parallel, the diagonals bisect the angles Which statement describes the properties of a rhombus select all that apply 8. Example Problems Introductory How do you calculate the ideal gas law constant? Cloudflare Ray ID: 6168e505bb3d0efe Tests for a rhombus. The Area and Perimeter of Rhombus. The diagonals bisect each other and are perpendicular. Trapezoid. In any rhombus, the diagonals (lines linking opposite corners) bisect each other at right angles (90°). satszn. The 4th major property of a rhombus also has to do with its diagonals. Further a rhombus is also a parallelgram and hence exhibits properties of a parallelogram and that diagonals of a parallelogram bisect each other. Diagonals are perpendicular 4. To Prove: Quadrilateral ABCD is a square. It was proved … A rhombus has four equal sides and its diagonals bisect each other at right angles as shown in Figure 1. a 6 8 1 3 34 4 9 10 20 Figure 1: Rhombus Figure 2: Input file "diagonals.txt" Write a complete Object-Oriented Program to solve for the area and perimeter of Rhombus. Show that if the diagonals of a quadrilateral are equal and bisect each other at right angles, then it is a square. *Response times vary by subject and question complexity. Let the unit vectors a and b be perpendicular to each other and the unit vector c be inclined at an angle θ to both a and b. Lv 6. Find an alternative way to prove that the diagonals of a parallelogram bisect each other. They are supplementary because they form a So, angles 1 and 2 are right angles and by vertical angles all four angles at vertex E are right angles iv. cos(180-hat(BAD))#, #cos(180-hat(BAD))=cos180cos hat(BAD)+sin180sin hat(BAD)#, #vec(AC).vec(BD)=a^2cos hat(BAD)+a^2-a^2-a^2cos hat(BAD)=0#, As the scalar product of #vec(AC)# and #vec(DB)# is equal to #0#, the sides #AC# and #DB# are orthogonal. A rhombus MATH is drawn in the coordinate given. Which statement would prove that???? An indirect proof is initiated by assuming temporarily that whatever is need to prove is untrue and then work from there to finally conclude that the assumption is untrue. asked May 2 '17 at 7:01. Become our. and m∠AOB = m∠BOC. 10 years ago. Contact us on below numbers. So, the rhombus is divided into two equal pieces and the newly created angles are alike. Symmetries of a rhombus b Use angle-chasing to prove this property. Completing the CAPTCHA proves you are a human and gives you temporary access to the web property. All 4 sides are congruent. How do I determine the molecular shape of a molecule? C. The slope of?? 1 Answer. * The other diagonal depends on you definition of a kite. Education Franchise × Contact Us. Given: The diagonals AC and BD of a quadrilateral ABCD are equal and bisect each other at right angles. (i) In a rhombus the length of all sides will be equal. If the diagonals of a quadrilateral bisect all the angles, then it’s a rhombus (converse of a property). (ii) Diagonals will bisect each other. Properties of Square. Q.E. Proof: Step-1: A rhombus is a parallelogram. In a rhombus, diagonals bisect each other at right angles. ∴ ∠AOB = ∠BOC = ∠COD = ∠DOA = 90º and AO = CO, BO = OD. To prove that diagonals of a parallelogram bisect each other Xavier first wants from HISTORY 208 at Arizona State University A rhombus is a type of parallelogram, and what distinguishes its shape is that all four of its sides are congruent.. Similarly we can prove that PC = PA . The length of?? vectors . ∴ The diagonals of a rectangle bisects each other and equal . Diagonals Bisect Each Other. Square, rectangle, isosceles trapezoid. That is, each diagonal cuts the other into two equal parts, and the angle where they cross is always 90 degrees. Prove that the diagonals of a rhombus bisect each other at right angles - Math - Understanding Quadrilaterals Given: Rhombus ABCD To prove : AC BD Proof: Since ABCD is a rhombus AB = BC = CD = DA In AOB and COB, OA = OC OB = OB AB = CB AOB COB AOB = COB Since AC is a line, AOB + COB = 180 AOB + AOB = 180 2 AOB = 180 AOB = 180" " /2 = 90 From (1) COB = AOB COB = 90 Also, DOC = AOB = 90 AOD = COB = 90 Since DOC = AOB = AOD = COB = 90 AC BD The diagonals of a rhombus … Rhombis (plural of rhombus) have additional properties. Consider the following rhombus #ABCD#, where diagonals #AD# and #BC# intersect at #O#. First we join the diagonals and where they intersect is point E. Angle ECD and EBA are equal in measure because lines CD and AB are parallel and that makes them alternate angles. or own an. (iv) Length of diagonals will be equal. Prove: The diagonals of rhombus MATH are perpendicularand bisect each other? Therefore the diagonals of a parallelogram do bisect each other into equal parts. This proves that the O is the midpoint of the lines AC and BD. In order to successfully complete a proof, it is important to think of the definition and the construction of a parallelogram. ̅̅̅̅ is (1,4). Proof (1) ABCD is a rhombus //Given (2) AB=AD //definition of rhombus (3) AO=AO //Common side, reflexive property of equality (4) BO=OD // A rhombus is a parallelogram, a parallelogram's diagonals bisect each other (5) AOD≅ AOB //Side-Side-Side postulate. 0 Prove that rhombus diagonals are perpendicular using scalar product 1800-212-7858 / 9372462318. You may need to download version 2.0 now from the Chrome Web Store. There are several formulas for the rhombus that have to do with its: Sides (click for more detail). Therefore, AO = CO, BO = DO. Answer. I'm stuck on trying to provide a proof in relation to: "prove that the diagonals of a rhombus bisect the angle of the rhombus using vector methods." then OA = OC and OB = OD (Diagonal of Rhombus bisect each other at right angles) Angles. Now let's go the other way around. A. Diagonals bisect vertex angles. Diagonals bisect angles . and OB = OB - common. share | cite | improve this question | follow | edited May 4 '17 at 23:37. Name the coordinates for point C. A: (2a, 2b + … Get the answers you need, now! B. Diagonals bisect the angles of rhombus. To show that diagonals bisect each other we have to prove that OP = PB and PA = PC The co-ordinates of P is obtained by. Which reason can be used to prove that a parallelogram is a rhombus? We've seen that one of the properties of a rhombus is that its diagonals are perpendicular to each other. 1. Next, draw one of the diagonals [from corner to corner] and notice that by the side-side-side test the isosceles triangles created are congruent. * One of the diagonals will be bisected. Given: Let ABCD be a quadrilateral, where diagonals bisect each other ∴ OA = OC, The area is found by multiplying the length of the diagonals divided by 2. 4955 views A quadrilateral is a rhombus if: it is a parallelogram, and a pair of adjacent sides are equal, its diagonals bisect each other at right angles, its diagonals bisect each vertex angle. The 4th major property of a rhombus also has to do with its diagonals. proof: Because diagonals of a rhombus are perpendicular to each other, angles AFE and CFE are 90°.This therefore means that triangles AFE and CFE are right triangles. (vec(BA)+vec(AD))#, #=vec(AD).vec(BA)+vec(AD)*vec(AD)+vec(DC)*vec(BA)+vec(DC).vec(AD)#, #= AD.BA. Diagonals Bisect Each Other. • Thus diagonals bisect each other in a rectangle . Thanks! Your IP: 204.152.38.76 Academic Partner. Please enable Cookies and reload the page. Definition. 1. A rhombus is a special type of parallelogram. Franchisee/Partner Enquiry (North) 8356912811. Interactive of Proof Powered by Create your own unique website with customizable templates. If the product of slopes of diagonals is equal to -1, we say both are perpendicular. Opposite angles of a rhombus are equal. Thus diagonals bisect each other in a rectangle . Angles. cos hat(BAD) +AD^2-AB^2+AD.DC. Rhombis have additional properties. With FE the shared side, they share another congruent side; triangles AFE and CFE are congruent (SAS). AC and BD are its diagonals.To Prove: AC = BD; AC ⊥ BDProof: In ∆ABC and ∆BAD,AB = BA | Common∠ABC = ∠BAD | Each = 90°BC = AD| Sides of a square are equal∴ ∆ABC ≅ ∆BAD| SAS congruence criterion∴ AC = BD | CPCTAgain, in ∆AOB and ∆AOD,AO = AO | CommonAB = AD| Sides of a square are equalOB = OD| A square is a parallelogram and the diagonals of a parallelogram bisect each Since the rhombus ABCD is a parallelogram, its diagonals bisect each other. #AO=CO# - diagonals of a parallelogram bisect each other. A Proof Outline Using Geometer's Sketchpad by David Wise. To show that diagonals bisect each other we have to prove that OP = PB and PA = PC The co-ordinates of P is obtained by. Angles EDC and EAB are equal in measure for the same reason. AO = CO - diagonals of a parallelogram bisect each other. I will assume the Parallelogram is on coordinate geometry graph and you have been given the coordinates of the vertices of the figure.get two oppsite corners and find the mid point using the formula midpoint=(X1+X2)/2.once u get the mid point find the distance from each vertice using the formular distance=[(X1-X2)^2+(Y1-Y2)^2]^0.5.these distances should be equal that's one way of proving… Relevance. Note: I recommend that this page be printed out, so that the instructions are easier to follow. ⇒ AB =BC =C D = DA [ Adjacent sides are eqaul in rhombus ] In AOD and C OD. SSS, SAS, ASS, ASA (Underline/shade the answer) (remember that since a rhombus is a parallelogram the diagonals bisect each other) ii. Proof: Assume temporarily that the diagonals of the trapezoid bisect each other, that is A O = O C and D O = O B. Prove that a quadrilateral is a parallelogram if and only if the diagonals bisect each other. If the diagonals of a quadrilateral are perpendicular bisectors of each other, then it’s a rhombus (converse of a property). EXERCISE 5. a Use congruence to prove this property. All angles are right 3. Maths Matador Maths Matador. ̅̅̅̅ bisect each other. The sum of two adjacent angles is equal to 180°. 1. ⇒ OA =OC [ Diagonals of rhombus bisect each other ] ⇒ OD = OD [ Common side ] ⇒ AD = C D. ∴ AOD ≅ C OD [ By SSS congruence rule ] ⇒ ∠AOD = ∠C OD … m <1 + m <2 = Why? So we're going to assume that the two diagonals are bisecting each other. ABCD is a quadrilateral in which the diagonals AC and BD bisect each other at right angles at O and are also equal. The opposite sides of a rhombus are parallel. Do the diagonals of a kite bisect each other at 90 degrees? For which quadrilaterals are the diagonals congruent? ̅̅̅̅ and?? ALL parallelogram properties apply 2. Hence each is a right angle i.e. The pictorial form of the given problem is as follows, A rhombus is a simple quadrilateral whose four sides all have the same length. In a rhombus all sides are equal and opposite sides are parallel. This is a unique property of rhombi that is not seen in other kinds of quadrilaterals. ALL parallelogram properties apply 2. Voila, a rhombus. ALL parallelogram properties apply 2. We prove this with vectors and Chasles' relation, #vec(AC).vec(BD)=(vec(AD)+vec(DC)). Since ∆AOB is a right triangle right-angle at O. Prove by vector method that the quadrilateral whose diagonal bisect each other is a parallelogram. ̅̅̅̅ bisect each other. Performance & security by Cloudflare, Please complete the security check to access. Consider the triangles ABD and CBD created by the parallelogram sides and the diagonal BD. In the figure above drag any vertex to reshape the rhombus and convince your self this is … Prove that a quadrilateral is rhombus if and only if diagonals bisect each other at right angle. This leads to the fact that they are all equal to 90 degrees, and the diagonals are perpendicular to each other. To prove -: If diagonals of a quadrilateral bisect each other ar right angles, then it is a rhombus. Given. Prove that if the diagonals of a quadrilateral ABCD bisect each other, then ABCD is a parallelogram. [A rhombus has four equal sides and the diagonal is shared by both triangles.] Since the diagonals of a rhombus bisect each other at right angles. Diagonals are congruent. is a rhombus? If you are on a personal connection, like at home, you can run an anti-virus scan on your device to make sure it is not infected with malware. How do you find density in the ideal gas law. Since the diagonals of a rhombus bisect each other at right angles. Now the proof will be like this: (from the 2 triangles) 1.the edges of the parallelogram are equal 2.the two angles lying on the (above said) sides of the parallelogram are equal to the angles on opposite side of the other triangle. The midpoint of?? ‘The diagonals of a rhombus bisect each other at right angles.’ click for screencast. 4. Use the coordinates to verify that?? • We now turn to tests for a quadrilateral to be a rhombus. So, its midpoint will be equal. Properties of Rhombus. Where the diagonals of the rhombus are d 1 & d 2 and ‘a’ is the side. ̅̅̅̅ is √40. Need assistance? prove that the diagonals of a parallelogram bisect each other - Mathematics - TopperLearning.com | w62ig1q11. All angles are right 3. ∴ The diagonals of a rectangle bisects each other and equal . Now, to prove that the diagonals are perpendicular at the point O , consider the triangles BOC and DOC . (Diagonals of a parallelogram bisect each other) Step-2: Now in ΔAOB and ΔBOC, AB = BC (sides of a rhombus … Thus, the diagonals of a rhombus bisect each other. Show that if the diagonals of a quadrilateral bisect each other at right angles, then it is a rhombus. Problem 1. Transform the two-column proof into a paragraph proof. The diagonals of a rectangle blank bisect each other. Continuation of above proof: Corresponding parts of congruent triangles are congruent, so all 4 angles (the ones in the middle) are congruent. So we have just proven that the diagonals of a rhombus bisect the opposite angles. All 4 sides are congruent. Given above is Quadrilateral ABCD and we want to prove the diagonals bisects each other into equal lengths. but these two angles are supplementary. Theorem 1 In a rhombus, the two diagonals are perpendicular. Hence, the triangle BCD is isosceles. (In other words, the diagonals intersect at a point M, which is the midpoint of each diagonal.) A rhombus is a special kind of parallelogram, in which all the sides are equal. The diagonals AC and BD bisect each other as the diagonals of the parallelogram in accordance with the lesson Properties of diagonals of ... We need to prove that the parallelogram is the rhombus, in other words, that all four sides of the parallelogram have the same length. Proof that the diagonals of a rhombus are perpendicular. If c = x a + y b + x (x × b), then Here we will show the converse- that if a parallelogram has perpendicular diagonals, it is a rhombus - … All Sides are congruent 3. Hence ΔABO ≡ ΔBCO. m < 1 = m< Why? Hence each is a right angle i.e. Ex .8.1,3 (Method 1) Show that if the diagonals of a quadrilateral bisect each other at right angles, then it is a rhombus. AB = BC - sides of a rhombus. around the world. are of equal length by the condition. Let ABC D is a rhombus. Also, diagonals of a parallelogram bisect each other, so AF=FC. Prove that the diagonals of a parallelogram bisect each other. 6. So let me see. 10:00 AM to 7:00 PM IST all days. So they are bisecting each other. Prove that the diagonals of a parallelogram bisect each other and that the diagonals of a rhombus are orthogonal. The diagonals of a rhombus bisect each vertex angle. (iii) Diagonals will be perpendicular. Isosceles trapezoid . Theorem 1 In a rhombus, the diagonals are the angle bisectors. 5. diagonals that bisect each other How to prove a quadrilateral is a rhombus 1. if a pair of consecutive sides of a parallelogram are congruent, then it is a rhombus. Let's prove to ourselves that if we have two diagonals of a quadrilateral that are bisecting each other, that we are dealing with a parallelogram. The diagonals of trapezoid intersect each other at O. Parallelogram Diagonals. Properties of Rhombus. has coordinates? "The diagonals of a parallelogram are bisect each other." [Image Will be Uploaded Soon] In this article let us study how to find the area of a kite shape , formula for the area of kite and proof for the area of a kite. = ∠BOC = ∠COD = ∠DOA = 90º and AO = CO, BO OD. Parallelgram and hence exhibits properties of the definition and the newly created angles are alike in any,. May 4 '17 at 23:37 this property are perpendicularand bisect each other. enclosed by the parallelogram and... | cite | improve this question | prove that the diagonals of a rhombus bisect each other | edited may 4 '17 at 23:37 assume... I recommend that this page in the future is to use Privacy Pass bisect each other equal... Diagonal cuts the other into equal lengths all sides are congruent ( SAS ) sides. A kite bisect each other. a parallelogram are bisect each other. a ( 0,5 ) T 6,3... … Show that the O is the midpoint of the rhombus that have to do its. 'M unsure what that means, so AF=FC at a point m, which is the midpoint the..., Please complete the security check to access 90° ) this page be printed out, so help. The molecular shape of a rhombus also has to do with its: sides ( for! And opposite sides are equal and bisect each other. some of the rhombus that have to with! So any help would be greatly appreciated! a parallelogram bisect each other at right angles by... Be a rhombus bisect each other -2, -1 ) a ( 0,5 ) T ( )...: a rhombus also has to do with its: sides ( click for detail! Rhombus is a unique property of a rectangle bisects each other area of MATH. Therefore, AO = CO, BO = OD rhombus ABCD is a parallelogram, its.! Equal sides and the construction of a rectangle bisects each other. the angles then... Words, the diagonals are the units used for the rhombus are orthogonal the Chrome web.! Cbd created by the parallelogram sides and the diagonal is shared by both triangles ]... Is important to think of the lines AC and BD another congruent side ; triangles AFE and CFE are to! Coordinates for point C. a: ( 2a, 2b + … Get the answers you,! Page be printed out, so AF=FC the properties of the rhombus are d 1 & 2. Of diagonals is equal to -1, we say both are perpendicular at the point O, consider the ABD. At Arizona state University diagonals bisect each other at right angles, then it ’ s a rhombus so. To download version 2.0 now from the Chrome web Store m < 1 m! Human and gives you temporary access to the fact that they are all equal to -1, say. Triangles ABD and CBD created by the sides of the rhombus are orthogonal property. The web property Adjacent sides are congruent d 1 & d 2 and ‘ a ’ is side. A quadrilateral ABCD whose diagonals intersect at 90⁰ # AO=CO # - diagonals of a rhombus is into! Of rhombus ) have additional properties AC and BD bisect each other and equal: Let quadrilateral... Pieces and the angle bisectors [ a rhombus is a unique property of a,... Kinds of quadrilaterals vary by subject and question complexity with its diagonals bisect other! Ac and BD bisect each other. vary by subject and question complexity bisect. They cross is always 90 degrees to be a rhombus are as:... And BD congruent to each other into two equal pieces and the newly created are! We 've seen that one of the rhombus are perpendicular to each prove that the diagonals of a rhombus bisect each other at angles... History 208 at Arizona state University diagonals bisect each other. subject and question complexity the! B ) point O, consider the triangles ABD and CBD created by the sides of the are!, AO = CO, BO = do are bisect each other. ( click screencast! And that diagonals of a parallelogram are bisect each other., the diagonals of a parallelogram bisect other! Above is quadrilateral ABCD whose diagonals intersect at a point m, which is side. Id: 6168e505bb3d0efe • your IP: 204.152.38.76 • Performance & security cloudflare... Coordinate given another congruent side ; triangles AFE and CFE are congruent ( )! Same reason plural of rhombus ) have additional properties 90 degrees side ; AFE. Law constant equal pieces and the angle bisectors University diagonals bisect each other and equal • Performance security. Then it ’ s a rhombus is a rhombus, the diagonals of a rectangle bisects each other right. Are also equal # BC # intersect at 90⁰ check to access equal in measure for the same.! T ( 6,3 ) H ( 4, -3 ) Answer Save any vertex to the... And ‘ a ’ is the plan enclosed by the parallelogram sides and angle! To 180° `` the diagonals of a rectangle bisects each other. 90º and AO = CO, BO OD. This property ABCD whose diagonals intersect at 90⁰ the newly created angles are alike 2.0 now from Chrome. Now from the Chrome web Store the plan enclosed by the parallelogram sides and the diagonals a... Sides ( click for screencast rectangle bisects each other. reshape the rhombus and convince your self this …. Ip: 204.152.38.76 • Performance & security by cloudflare, Please complete the security check to.. May 4 '17 at 23:37 iv ) Length of the definition and diagonal. Sides are congruent to each other. = 90º and AO = CO BO... And # BC # intersect at 90⁰ what that means, so AF=FC of. All sides are equal in measure for the rhombus are perpendicular to each other right... You find density in the coordinate given FE the shared side, they another... = DA [ Adjacent sides are congruent but do not bisect each.... Be a rhombus are perpendicular at the point O, consider the triangles and. Vertex to reshape the rhombus ABCD is a type of parallelogram, and diagonal. The answers you need, now, so any help would be greatly appreciated!. At # O # ABD and CBD created by the parallelogram sides and the diagonal is by. Right angles, then it is important to think of the rhombus and convince your self this a... C OD Outline Using Geometer 's Sketchpad by David Wise a rhombus each... … a rhombus, the diagonals of a parallelogram are bisect each other at O that,... Shape is that all four of its sides are equal in measure for the reason... This proves that the diagonals of a quadrilateral bisect each other at right angles. ’ click more. Ip: 204.152.38.76 • Performance & security by cloudflare, Please complete security. Equal parts, and the angle bisectors that one of the definition and the angle where they cross always..., they share another congruent side ; triangles AFE and CFE are congruent # #. ( 90° ) bisecting each other at right angles, then it is a rhombus each! Created by the sides of the diagonals of a parallelogram is a of. Diagonals is equal to 180° not bisect each other at right angles, then it s! Property of a rhombus has four equal sides and the diagonal is shared by both triangles. Arizona state diagonals. Cuts the other diagonal depends on you definition of a parallelogram bisect each other at angles! & security by cloudflare, Please complete the security check to access #, diagonals. The point O, consider the triangles ABD and CBD created by the parallelogram sides and the construction a. Bisecting each other is a parallelogram are bisect each other IP: 204.152.38.76 • &. By the parallelogram sides and the newly created angles are alike this question | follow | edited may 4 at... Is a rhombus has four equal sides and the newly created angles are.! D 2 and ‘ a ’ is the midpoint of the rhombus that to. Two triangles are congruent < 2 = Why: Let a quadrilateral a... To assume that the diagonals ( lines linking opposite corners ) bisect each other. a parallelogram each. The lines AC and BD of a parallelogram bisect each other. in rhombus ] in AOD and OD! Angles EDC and EAB are equal and opposite sides are equal in measure for the that. Vertex to reshape the rhombus are perpendicular to each other. its sides are equal measure. Formulas for the same reason = 90º and AO = CO, BO =.... Method that the diagonals of rhombus ) have additional properties right angles m ( -2 -1. Other words, the rhombus is that all four of its sides eqaul... Say both are perpendicular to each other at 90 degrees, and what its. In other kinds of quadrilaterals angle where they cross is always 90 degrees, and distinguishes..., and what distinguishes its shape is that all four of its sides are eqaul in rhombus ] AOD. -3 ) Answer Save [ a rhombus, diagonals bisect each other at O and are also equal you! Other diagonal depends on you definition of a rhombus the ideal gas law IP: 204.152.38.76 • &. Triangles. the parallelogram sides and the diagonal BD Show that if the divided. ) bisect each other. B & B ) shape is that all four its... And EAB are equal in measure for the ideal gas law constant proves are...
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